Question

is the \( \ne \) relation on N transitive?

Answer 1

Like if \( x \ne y \) and \( y \ne z\) does that mean that \( x \ne z \) ?

Answer 2

yeaah !

Answer 3

okkkkkkk gotcha

Answer 4

Thanks

Answer 5

the anwser ! .? true or false ?

Answer 6

noooo like is this relation transitive or not?

Answer 7

you're proving that property isn't true ! an example can be an answer !

Answer 8

a counter-example could be an answer

Answer 9

waiiitt is this relation transitive?

Answer 10

i thought it was

Answer 11

1 ! = 3
3 != 1
1 != 1 (false)

Answer 12

ohhh so x can equal z ohhhh

Answer 13

it must not be\[1\neq2\]\[2\neq1\]\[1=1\]false yeah

Answer 14

okkkkk thanksssssss

Answer 15

i was gettting a lil bit confused there

Answer 16

me too this is all new to me, but it makes sense...

Answer 17

well ... on the other hand ... = is transitive

Answer 18

that's a separate matter
= is transitive and symmetric

Answer 19

and relflexive since x=x

Answer 20

ah yeah, indeed :)

Answer 21

umm wld u say that the divide relation is transitive?

Answer 22

algebra stuff ..

Answer 23

how can an operator be transitive?

Answer 24

like if x divides y and y divides z does x divide z?

Answer 25

lol ... divides is a relation and it does.
12, 4, 2

Answer 26

i wld say its transitive i mean like with this example it does if 12 divides 6 and 6 divides 3 then 12 divides 3

Answer 27

well ... yes it is

Answer 28

reflexive ... but not symmetric.

Answer 29

yaaaaaaaaa

Answer 30

I have another question but ill open a new post since its gettting too long

Answer 31

sure