Question

Find the Solution of 2cos^2x + 3sin x =0

Answer 1

2cos^2x + 3sin x =0
2(1-sin^2x) + 3sinx = 0
-2sin^2x + 3sinx +2 = 0
2sin^2x -3sinx -2 = 0
(2sinx +1)(sinx-2) = 0
Solve for x

Answer 2

sinx - 2 =0

sinx = 2

Answer 3

2sin^2 x = 1

sin^2 x = 1/2

Answer 4

2sin^2 x = 1 <- not really!

Answer 5

sinx = 2 not posiible

Answer 6

sin^2 x =- 1/2

Answer 7

sin x = -1/2

Answer 8

x = sin (180 +150) and sin(360-330)

Answer 9

x=arcsin(-1/2)

Answer 10

sin^2 x =- 1/2 <- incorrect
sin x = -1/2 <- correct
x = sin (180 +150) and sin(360-330) <- not correct

It should be \(x = sin^{-1} (-1/2)\)

Answer 11

or x =11pie/6

Answer 12

I made it correct u see

Answer 13

we will have two values for x

Answer 14

correct

Answer 15

When you get the step
sinx = -1/2
You should take arc sine for both sides to solve x
sin^-1 (sinx) = sin^-1(-1/2)
x = -30 or x = 180+30

Answer 16

This is because there are two values for x in which sinx = -1/2

Answer 17

wat r they!!

Answer 18

What do you mean?

Answer 19

we need to find solution such npie + (-1)^n y

Answer 20

What is sin^-1 (-1/2)?

Answer 21

i dont knw

Answer 22

What value of x can give you -1/2 when you take sine of that value?

Answer 23

No idea!

Answer 24

What given you 1/2 when you take sine of that value??

Answer 25

30

Answer 26

pie/6

Answer 27

And??

Answer 28

wat??

Answer 29

sin(360-330) = sin330 = sin11pie/6

Answer 30

sin(360-330) ≠ sin330 !!!

Answer 31

sin(2pie - 11pie/6) =?

Answer 32

sin(2pie - 11pie/6) = sin (pi/6) = 1/2

Answer 33

ok......PLzz teach me hw to take inverse function

Answer 34

Think in this way, when you take sine of a function, what values would give you -1/2?

Answer 35

ok...then it should lie in 3rd or 4th quadrant

Answer 36

Yes, but are the values?

Answer 37

values hw to find..

Answer 38

http://web.gccaz.edu/~jgutier5/Tables/The%20Unit%20Circle%20Table%20Of%20Values.pdf

Answer 39

Consider quadrant I,
sin (pi/6) = 1/2

Consider quadrant II,
sin (pi - pi/6) = 1/2

Consider quadrant III,
sin (pi + pi/6) = -1/2

Consider quadrant IV,
sin (2pi - pi/6) = -1/2

Got it?

Answer 40

thxxx a lot

Answer 41

You're welcome.