Question

HELP PLEASE!!!!!
solve 6cos theta+2=0

Answer 1

\[6\cos \theta +2=\]

Answer 2

a=109.5
b=30.7
c=28.6
d=70.5

Answer 3

what's theta?

Answer 4

θ= theta

Answer 5

There's gotta be another piece of information in that problem...can you look again?

Answer 6

6 cos theta + 2 = 0

Answer 7

\[6\cos(\theta) = -2\]

\[\cos(\theta) = \frac{-1}{3} \implies \theta = \cos^{-1}(\frac{-1}{3})\]

\[\theta = \cos^{-1}(\frac{1}{3}) \implies 70.73 \approx 70.5\]

Answer 8

d=70.5

Answer 9

thank you could you also help me with a few others??

Answer 10

Not sure but I will try..

Answer 11

\[\sin ^{2}x+3 sin x+2=0\]

Answer 12

u there @waterineyes

Answer 13

Here its 2:11 am..
I am falling asleep..


Here you can factorize it:

\[\sin ^{2}x+3 \sin x+2=0 \implies (sinx+2)(sinx + 1) = 0\]

Put them separately equal to 0 and find sinx from there..