Question

2x^3+22x^2+36x solve the cubic equation by factoring out the gcf first

Answer 1

gcf is 2x

Answer 2

yes

Answer 3

what do you have when you have factored it out

Answer 4

i relly dont know

Answer 5

2x(x^2+11x+18)
2x(x-9)(x-2)
this is all he wants @UnkleRhaukus

Answer 6

\[2x^3+22x^2+36x\Longrightarrow 2x\left(\frac{2x^3}{2x}+\frac{22x^2}{2x}+\frac{36x}{2x}\right)\]

Answer 7

yeah but thats hardly an explanation theyatin

Answer 8

please ellaborate

Answer 9

cancel the gfc like this
\[2x\left(\frac{2x^3}{2x}+\frac{22x^2}{2x}+\frac{36x}{2x}\right)\Longrightarrow 2x\left(\frac{\cancel {2x}\times x^{2}}{\cancel{2x}}+\frac{\cancel{2x}\times11x}{\cancel{2x}}+\frac{\cancel{2x}\times16}{\cancel{2x}}\right)\]

Answer 10

whops 36≠2x16
36=2x18

Answer 11

so now you have a quadratic in the brackets

Answer 12

k

Answer 13

the solutions for x are the values x can be for the equation to be true , but you dont have an equation

Answer 14

okthnk

Answer 15

=0?