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What is the equation of the line in standard form that passes through the point (3, 4) and is parallel to the line y = –x + 6?
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Well if two lines are parallel they both have the same slope. What is the slope of y=-x+6 ?
1?
*-1
yes!
So we know the slope of the line we are about to create is -1
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The standard form of a line looks like this: \[Ax+ By = C\]
ax+by=-1?
but that doesnt really help us cause I don't see slope anywhere.... We have slope and we have a point, so lets use point slope form, then switch back to the form they want. Point slope form is \[(y - y_1) = m (x - x_1)\]
y1 is given x1 is given and now we know m
Thats all we need.. just plug those in and move stuff around until it is in standard form
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