Question

I know how to do the following, but it's a bit confusing:

Prove: Every point on the perpendicular bisector of a segment is equidistant from the ends of the segment.

https://media.glynlyon.com/a_matgeo_2011/8/q424a.gif

AP = BP

AP = ?
BP = ?

Answer 1

AP^2 = (-a)^2 + (b)^2 = a^2 + b^2
BP^2 = a^2 + b^2
so AP^2 = BP^2

Answer 2

- there one more step

Answer 3

\[\sqrt{a ^{2}+b^{2}}\]

Answer 4

That's the answer I got.

Answer 5

yes

Answer 6

Thanks!

Answer 7

yw