Question

Bob has $2.90 in pennies, nickels, and dimes. He has the same number of pennies and nickels. If the number of dimes is 5 more than the number of nickels, how many of each type coin does he have?

Answer 1

let
x=no. of pennies and nickels
x+5 = no. of dimes
.01x+.05x+.10(x+5)=2.90
.06x+.10x+.50=2.90
.16x=2.90-.50=2.40
.16x=2.40
x=2.40/.16=15

=>15 pennies
=>15 nickels
=>20 dimes

Answer 2

hope it'll help :)

Answer 3

Thank you

Answer 4

mention not bro :)