Question

If P(x)=(x-a)Q(x), where Q(x) is a polynomial, explain why p(a)=0???

Answer 1

because (x-a) is a factor...and according to remainder theorem if x-a is a factor then p(a) = 0

Answer 2

or simply replace \(x\) by \(a\) and see what you get

Answer 3

and also because if you sub a into x you get a-a = 0

Answer 4

oh so because (a-a)=0, 0xQ(a)=0 also.

Answer 5

yup