Part 1: Fill in the missing row of the truth table.
Part 2: Are the two statements logically equivalent? Why or why not?
~(p ∧ q) and (p ∨ ~q)
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OpenStudy (anonymous):
OpenStudy (anonymous):
May someone help me?
OpenStudy (anonymous):
i dont know where part is missing
OpenStudy (anonymous):
second to the bottom
OpenStudy (anonymous):
oh i see F T F F T F F
~(p ∧ q) and (p ∨ ~q)
1. ~(true) and (true) = false and true not equivalent
2. ~(false) and (true)= true and true equivalent
3. ~(FALSE) and (false) = true and false not equivalent
4. ~(false) and (true) = true and true equivalent
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OpenStudy (anonymous):
Thanks! But could you help me understand it, a bit more?
OpenStudy (anonymous):
for p and q we already have TT TF and FF , that's why we just combination of FT
so p = F and q= T
OpenStudy (anonymous):
we just need*
OpenStudy (anonymous):
after we got p = F and q = T then of course ~q = F
got it ?
OpenStudy (anonymous):
ok. THANKS!
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OpenStudy (anonymous):
next p ^ q = F ^ T = ?
remember ^ means 'and' and v means 'or'