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find the point on the line y=x nearest to the point (4,1). THe ans. is (5/2,5/2)
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geometry or calculus?
calculus
whew, then it is easy
ok show to me :D
any point on the line \(y=x\) will look like \((x,x)\) and the square of the distance between any point \((x,x)\) and \((4,1)\) is \[f(x)=(x-4)^2+(x-1)^2\]
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multiply out, combine like terms, take the derivative, set it equal to zero and solve for \(x\)
in fact you don't need calculus because \(f\) is a quadratic, and it will have a minimum at the vertex
you good from there?
ok :D thats all master ???
that is it, unless you need help with the algebra
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