Question

Please solve this integration

Answer 1

\[\int\limits_{0}^{1}lnxdx \div(1+lnx)^{2} = I ?\]

Answer 2

Where,(1+lnx) is +ve
and
lnx<0 for all x between 0 to 1
a(Upper limit)>0

Answer 3

ln means logx

Answer 4

Do you know that wolframalpha is pretty good at doing stuff like this..

Answer 5

Is the answer x/(1+log(x)) ?

Answer 6

Well, no, because you have to put in the limits as well. There should be a numerical answer at the end

Answer 7

What would be the final answer?

Answer 8

http://www.wolframalpha.com/input/?i=integrate+%28ln+x%29%2F%281%2B+ln+x%29^2+from+0+to+1
integral does not converge