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OpenStudy (anonymous):
OpenStudy (anonymous):
Use Pythagorus theorem to solve. Do you know how to do that?
OpenStudy (anonymous):
In this case, you can also use pythagorus triples.
OpenStudy (anonymous):
what are the numbers? I cant read them
OpenStudy (anonymous):
A2+b2=c2?
I keep trying to plug it in but I cant get the right answer.
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OpenStudy (anonymous):
you need to divide 6 by 2.
OpenStudy (anonymous):
The hight is 4 and the base is 6
OpenStudy (anonymous):
the base is 3, the height is 4. What is the hypotenuse?
OpenStudy (anonymous):
base is 3 because pythagorus theorem works only on 90 degree triangles.
OpenStudy (anonymous):
so make it two right angle triangles. Now you have 3,4 and...?
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OpenStudy (anonymous):
Maybe, Am I suppost to add 3 an for to get x? or?
OpenStudy (anonymous):
four*
OpenStudy (anonymous):
\[3^2+4^2=x^2\]
OpenStudy (anonymous):
you add the square of the base and the square of the height to get the hypotenuse so yes, you add them.
OpenStudy (anonymous):
after you find x, this is the equation for the perimeter.
2x+6
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OpenStudy (anonymous):
Okay I get that, now how do I solve the equation, this is where I get stuck.
OpenStudy (anonymous):
have you found x?
OpenStudy (anonymous):
I thought it was 7, but i'm not very sure.
OpenStudy (anonymous):
what is (3*3)+(4*4)=?
OpenStudy (anonymous):
9 + 16 = 25
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OpenStudy (anonymous):
correct. now, 25 = x^2
how to find x? (I'll rewrite the equation)
x^2=25
OpenStudy (anonymous):
12.5?
OpenStudy (anonymous):
\[x^2=25\]
OpenStudy (anonymous):
\[x=\sqrt{25}\]
OpenStudy (anonymous):
when you transfer square over to the other side, it becomes a square root.
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OpenStudy (anonymous):
do you know what the square root of 25 is?
OpenStudy (anonymous):
it's 5
OpenStudy (anonymous):
yes. so now we know that x is 5.
Now, there are two hypotenuse. So the equation would be
2x+6 or x+x+6
Since now we know that x=5, plug it into either one of the equations.