find the coordinates, of the top of this function: y = x^2 + 2x
so you're looking for maximum huh...do you know calculus?
just a little bit
okay..good enough...do you know how to take the derivative of this thing?
yes
so what's the derivative?
y' = 2x + 2
right. now take the derivative of this thing again...if the result is positive that means it's a minimum....if it's negative then it's a maximum...
Y'' = 2, so its a maximum?
nope...it's positive..therefore it's a minimum
that means this graph doesnt have a maximum
here's a picture of the graph :D http://www.wolframalpha.com/input/?i=y+%3D+x%5E2+%2B+2x it doesnt have a "top"
ow oke
then i have to find the coordinates of the bottom
oh goodie...then it's just the minimum..
you have y' = 2x + 2 right?
now equate 2x + 2 to 0 and solve for x what do you get?
x = 1
-1*
ok, then just fill in -1, in the original function or in the derivative function?
now substitute -1 for x in y = x^2 + 2x and solve for y
original function
ok thnx now I get it
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