sketch the graph of y=sec^2(x^2) on the interval[0,pi^1/2]. If the region is bounded by this graph and the x-axis over the interval is revolved about the y-axis find its volume. I know what the graph looks like i'm just unsure of what method to use to find the volume.

Question

anonymous · Answer

I believe the easiest thing you might could do with this integral is using the shell method.

$$ \Large 2 \pi \int_a^bx \cdot \sec^2(x^2)dx $$

and a proper u-Substitution.

anonymous · Answer

Hope that helps @dburfield, if you get stuck give me a nudge.