Question

Solve (x+1)^2-28=0, where x is a real number.
pleeeaaasse help!!!

Answer 1

expand (x+1)^2 first
\[\implies x^2 + 2x + 1 - 28 = 0\]
\[\implies x^2 + 2x - 27 = 0\]
does that help?

Answer 2

ohhhh! YES thank you!!!

Answer 3

welcome ^_^

Answer 4

hold up, what do i do next??

Answer 5

quadratic formula :D

Answer 6

\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
you know how to use it right?

Answer 7

ohh got it! thank you!

Answer 8

welcome ^_^