Question

If \[x/aCOS \alpha+y/bSIN \alpha =1 and x/aCOS \beta+y/bSIN \beta = 1\]
and \[COS \alpha COS \beta /a ^{2}+SIN \alpha SIN \beta/b ^{2} = 0\]
Then prove that
a)\[x ^{2}+y ^{2}=a ^{2}+b ^{2}\] and b) \[\tan \alpha \tan \beta = b ^{2}(x ^{2}-a ^{2})/a ^{2}(y ^{2}-b ^{2})\]

Answer 1

Can somebody help me solve this???