Very confused on these particular problems...no clue what it's talking about...

Question

anonymous · Answer

attachment

anonymous · Answer

@ganeshie8 I figured out C(x), but I don't get P(x)

ganeshie8 · Answer

For 16th question, i think P(X) = 4C2

hartnn · Answer

the two element group...say there are 4 elements,ABCD,there will be 16 2 element grp,AA,AB,AC,....DD....but if repetition like AA are not allowed,then there will be 12...and if AB and BA are considered same ,then there will be 6....

anonymous · Answer

I am getting B for the first one.

anonymous · Answer

Because I did xP2 = P(x) and (n - 1)! = C(x)

anonymous · Answer

Or would it be xC2 = P(x)?

ganeshie8 · Answer

oh i see... but i guess forming  2 element groups involves just choosing elements, order doesnt matter...

anonymous · Answer

Oh ok...then I get D for 16 and B for 17. I ddin't realize that, I was still thinking about the other part of the problem.

hartnn · Answer

if order doe not matter,then AB and BA are same,then use xC2

anonymous · Answer

Ok, then it would be:
16. D
17. B
?

ganeshie8 · Answer

yeah i guess that it.... .

anonymous · Answer

Alright. Thanks :)

ganeshie8 · Answer

np... :)