Question

What is the solution to the equation = 1 over the square root of 8= 4^(m – 2) ?

Answer 1

\[\log_6 x + \log_6(x + 1) = 1 \]Now use the property:\[ \log_na + \log_nb = \log_nab\]

Answer 2

hmmm

Answer 3

i messed up by accident ha

Answer 4

\[\frac{1}{\sqrt{8}}=2^{-\frac{3}{2}}\]

Answer 5

\[\left((2^3)^{1 \over 2}\right)^{-1}= (2^2)^{m - 2} \]

Answer 6

\[2^{-1.5} = 2^{2m - 4} \]Now you can equate the exponents.

Answer 7

swaggg , thanks .

Answer 8

You're welcome.

Answer 9

Dirty answer, isn't it?