Question

Problem set 3

I'm working on this: http://pastebin.com/RwMRZzWr

Specifically, I'm working on the 'play_hand' function. I'm trying to put all the functions I have into a workable game. The game is scrabble, btw.

I'm trying to create a loop that runs as long as a hand exists. The hand is a dictionary (keys are letters and values are # of instances), and for each word submitted, the letters are deleted from the dictionary.

How do I write a statement basically saying "while 'hand' has any value > 1, do this"?

Thanks in advance!

Answer 1

at line 234 you set n = len(hand) Can you just use while n > 1 at that point if you update n each time you play a word?

I think some combination like

while (n > 1) and (word != '.')

would likely do the trick

Answer 2

how about:
while max(dictionary.values()) > 0
http://dpaste.com/786132/

Answer 3

kudos bwCA. Worked perfectly. Appreciate the help :)