Please help! Perform the indicated operation. Leave all answers in the form a + b i. (1 - i ) (2 + 3 i ) a. -1 - 5 i b. -1 + i c. 5 + i d. 5 - 5 i
do u know this: (a+b)(c+d)=ac+ad+bc+bd ?
I'm familiar. Hmmm, so that's what I use?
and also the fact that i*i = -1 just try it....
\[\large{(1-i)(2+3i)=1(2+3i)-i(2+3i)}\] \[\large{(1-i)(2+3i)=1(2)+1(3i)-i(2)-i(3i)}\] this is the use of taht @IloveCharlie
*that
Hmm... :/
d.
what is i(3i) ?
i * 3i = 3 i ^2 = 3(-1) = -3 2+3i-2i+3 5+i
i(3i)=-3 @mathslover
9+2i?
:/
@mathslover already gave u answer,see the comments....
Yes but I can't match it up :/
he gave u answer as 5+i,which is option c here are all steps together: (1−i)(2+3i) =1(2)+1(3i)−i(2)−i(3i) =2+3i-2i+3 =5+i
Oh I understood I just must have missed it. Thank you for explaining the steps BOTH of you I appreciate it
Oh sorry yes : i *3 i =3 i^2 = -3
Join our real-time social learning platform and learn together with your friends!