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Mathematics 91 Online
OpenStudy (anonymous):

Assuming the balls to be identical expect for difference in colour the number of ways in which one or more balls can be selected from 10 white . 9 green and 7 black?

OpenStudy (anonymous):

@experimentX @kartiksriramk

OpenStudy (experimentx):

how many??

OpenStudy (anonymous):

wat

OpenStudy (anonymous):

balls to be selected

OpenStudy (anonymous):

Number of ways to do this = 11 x 10 x 8

OpenStudy (experimentx):

how many balls do you have to select? is it general case?

OpenStudy (anonymous):

One or more balls..

OpenStudy (anonymous):

Sorry, 11*10*8 - 1.You said one or more right?

OpenStudy (anonymous):

hw @siddhantsharan

OpenStudy (anonymous):

No of ways to select white ball : Select none----1 Select 1.-----2 Select 2------3 . . . Select 10 -----11 Total ways = 11 ways. Similarly for the green and black. Now, you subtract the one case where no ball will be selected.

OpenStudy (anonymous):

Is 879 correct?

OpenStudy (anonymous):

yup u r correct

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