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OpenStudy (anonymous):
Assuming the balls to be identical expect for difference in colour the number of ways in which one or more balls can be selected from 10 white . 9 green and 7 black?
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OpenStudy (anonymous):
@experimentX @kartiksriramk
OpenStudy (experimentx):
how many??
OpenStudy (anonymous):
wat
OpenStudy (anonymous):
balls to be selected
OpenStudy (anonymous):
Number of ways to do this = 11 x 10 x 8
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OpenStudy (experimentx):
how many balls do you have to select? is it general case?
OpenStudy (anonymous):
One or more balls..
OpenStudy (anonymous):
Sorry, 11*10*8 - 1.You said one or more right?
OpenStudy (anonymous):
hw @siddhantsharan
OpenStudy (anonymous):
No of ways to select white ball : Select none----1 Select 1.-----2 Select 2------3 . . . Select 10 -----11 Total ways = 11 ways. Similarly for the green and black. Now, you subtract the one case where no ball will be selected.
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OpenStudy (anonymous):
Is 879 correct?
OpenStudy (anonymous):
yup u r correct
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