Question

For all x>4, what is the value of (4x-x^2)/(x+3)(x-4)?

A. -1/12

B. 1/12

C. x/(x-3)

D. -x/(x+3)

E. x/(x+3)

Answer 1

\[\cfrac {x(4-x)}{(x+3)(x-4)}\]

You can solve it now

Answer 2

\[\large \color{red}{(4-x)} = \color {green}{-(x-4)}\]

Answer 3

do it further

Answer 4

Got it ?

Answer 5

solve for x?

Answer 6

It can\t be solved for x as we get

\[\large \cfrac{-x}{x+3}\]

Now, for all x>4 we will have different values of this fraction

Answer 7

so is that our final answer?

Answer 8

yes

Answer 9

it was given x>4 so that we can cancel out (4-x) and (x-4)

Answer 10

because if x = 4 then x-4 will become 0 and the fraction will not exist