Question

Id

Answer 1

Hint:

The x coordinate of the vertex of y = ax^2 + bx + c is

x = -b/(2a)

Answer 2

you're welcome, tell me what you get

Answer 3

close, but not quite

Answer 4

still no

Answer 5

y = -3x^2 + 6x - 2


y + 2 = -3x^2 + 6x


y + 2 = -3(x^2 - 2x)


y + 2 = -3(x^2 - 2x + 1 - 1)


y + 2 = -3((x^2 - 2x + 1) - 1)


y + 2 = -3(x^2 - 2x + 1) + 3


y = -3(x^2 - 2x + 1) + 3 - 2


y = -3(x - 1)^2 + 1

Answer 6

That's the correct way to complete the square