Question

Find the inverse of f(x) = [(2x+1)/(3x-1)]

Answer 1

My work so far:

y = [(2x+1)/(3x-1)]
x = [(2y+1)/(3y-1)]
x(3y-1) = (2y+1)

I get lost here ^.

Answer 2

isolate \(y\)

Answer 3

\[3xy-x=2y+1\]\[3xy-2y=x+1\] ?

Answer 4

Great, it looks clear to me now. So y = [(x+1)/(3x-2)] then? Pretty sure that's correct. Thanks again.

Answer 5

very well :)