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What are the x-intercept(s) of the graph of y − 3 = x2 + 4x?
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rewrite the equation as \[y = x^2 + 4x + 3\] can you factorise this..?
to find the x- intercepts let y = 0 then \[x^2 + 4x + 3 = 0\]
but like isnt it a rule that a cant equal 0?
the rule for x intercepts is that y = 0.... you are finding the points on the x-axis.... this is where y is always equal to zero
no. A cant equal zero... and it does in this equation
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you let the equation equal zero \[x^2 + 4x + 3 = 0\] so can you factorise
@marmar3000 , if you're referring to the coefficients in the equation \(\large y=ax^2+bx+c \), then in your equation a is not zero...
now you need to find the factors of 3 that add to 4
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