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Mathematics 25 Online
OpenStudy (anonymous):

sin^-1 [(radical 3)/2] (in the first quadrant)

OpenStudy (anonymous):

basically find sin rad3/2 in the first quadrant in the unit circle

OpenStudy (anonymous):

cos are the x values sin is the y values in it

OpenStudy (anonymous):

so i would be looking at 60 degrees in the first quadrant?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

well what do i do with it, is that all? isn't sin prime does it alter the answer?

OpenStudy (anonymous):

60 degrees or pie/3 is your answer, there the same thing, not sure what you mean with the second part of your question

OpenStudy (anonymous):

in my problem it is typed as: sin^-1 is that the same as the original sin?

OpenStudy (anonymous):

no its the inverse

OpenStudy (anonymous):

when given a inverse problem i always say where in the unit circle is this value located

OpenStudy (anonymous):

you just happen to be limited to quadrant 1 for your problem

OpenStudy (anonymous):

oh ok thank you

OpenStudy (anonymous):

np

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