Question

WHAT IS THE ECCENTRICITY OF THE GRAPH OF [(X-2)^2/121]+[(Y+6)^2/64]=1?

Answer 1

b^2 = a^2( 1 - e^2)

for x^1 / a^2 + y^2 / b^2 = 1

Answer 2

huh?

Answer 3

compare the denominators in the question with the above
a^2 = 121 and b^2 = 64

e = eccentricity

Answer 4

so substituting in the formula

64 = 121(1 - e^2)
121e^2 = 121 - 64
e^2 = 57 / 121

can you finish this?

Answer 5

yea i got it thanks

Answer 6

yw