Question

How to integrate this: ln(2x+1) dx. I tried use integration by parts. But unsuccessful.

Answer 1

ln(u) integrates to u ln(u) - u

by tables :)

Answer 2

integration by parts does work it out; you just have to use 1 dx your "dv"

Answer 3

\[\int ln(u)du=u~lnu-\int \frac{1}{u}u~du\]

Answer 4

But, I go to this integral:

X/(2x+1)dx and I not know how to integrate this ^^

Answer 5

\[\int \frac{2x}{2x+1} \text{d}x\]?

Answer 6

Yes

Answer 7

\[ \frac{2x}{2x+1}=\frac{2x+1-1}{2x+1}=1-\frac{1}{2x+1} \]does that help?

Answer 8

Thanks! I had forgot to use this

Answer 9

np :)