Question

HELPPP!!!
Find the sum of the even numbers from 1 to 200 inclusive.

Answer 1

does anyone know??

Answer 2

=2 + 4 + ... + 200
=2(1+2+3+...+100)
=2*((101*100)/2)
= 101*100
=10100

Answer 3

im not doubting u but are u positive on this answer @jeanlouie

Answer 4

don't doubt him/her. 10100 is correct.

Answer 5

ok thank you @helder_edwin

Answer 6

thank you also @jeanlouie

Answer 7

hope that help :)

Answer 8

can either of you answer this one?>>>sin θ = -3/5, find sin 2θ given that θ is in the 3rd quadrant.

Answer 9

θ is in the 3rd quadrant then cosθ < 0.
(sinθ)^2 + (cosθ)^2 = 1
=> (cosθ)^2= 1-(-3/5)^2 = 16/25
=> cosθ = -4/5
So, sin2θ = 2sinθcosθ = 2 * (-3/5) * (-4/5) = 24/25

Answer 10

do u think u could help me with some more but um going to close this question and open a new one and thank u