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Mathematics 9 Online
OpenStudy (anonymous):

I will post a graph and using it you have to figure out 4 things. (i.) (lim x->60-) f(x) (ii.) (lim x->60+) f(x) (iii.) What can you conclude about (lim x->60) f(x)? How is this shown by the graph? (iv.) What aspect of costs of renting a car causes the graph to jump vertically by the same amount at its discontinuities?

OpenStudy (anonymous):

OpenStudy (helder_edwin):

do u know what \(x\to60-\) means??

OpenStudy (anonymous):

as x approaches 60

OpenStudy (anonymous):

from the left

OpenStudy (anonymous):

@helder_edwin

OpenStudy (helder_edwin):

yes. sorry, my laptop's battery went down.

OpenStudy (helder_edwin):

now put yourself a little bit to the left of x=60 and then go up until u meet the function and then follow tha graph going leftwards with passing x=60

OpenStudy (anonymous):

will the answer be the closed dot or the open dot at x=60?

OpenStudy (helder_edwin):

if u go up a llitle bit to the left of x=60 u get to y=68 right?

OpenStudy (anonymous):

yes

OpenStudy (helder_edwin):

sorry gotta go!! remember \(x\to60-\) means x approaches 60 from the left but it never actually reaches x=60 so \[ \large \lim_{x\to60-}f(x)=68 \] in your graph.

OpenStudy (anonymous):

ok so (i.) is 68 so (ii.) is 68 too?

OpenStudy (anonymous):

recheck it (i.) is 56

OpenStudy (anonymous):

but u r right (ii.) is 68

OpenStudy (anonymous):

i think 1) (i) is 56 bcz it is to the left of 60 2) is 68 3) i think one sides limit exist at 60 not two sided

OpenStudy (anonymous):

@mukushla yes ur right sorry

OpenStudy (anonymous):

np sara :)

OpenStudy (anonymous):

as u can see and aliza mentioned (lim x->60-) f(x) \(\neq\) (lim x->60+) f(x) so the limit (lim x->60) f(x) does not exist.

OpenStudy (anonymous):

but the lim x->60- and lim x->60+ do exist right? and what would the answers be to these questions? (iii.) How is this shown by the graph? (iv.) What aspect of costs of renting a car causes the graph to jump vertically by the same amount at its discontinuities?

jimthompson5910 (jim_thompson5910):

yes the left and right hand limits exist, just not the limit itself

jimthompson5910 (jim_thompson5910):

left hand limit is shown and found by approaching x=60 from the left right hand limit is shown and found by approaching x=60 from the right

jimthompson5910 (jim_thompson5910):

basically what the previous posters said

OpenStudy (anonymous):

but (iii.) How is this shown by the graph? (iv.) What aspect of costs of renting a car causes the graph to jump vertically by the same amount at its discontinuities?

OpenStudy (anonymous):

(iii) there is no limit but how is this shown by the graph?

jimthompson5910 (jim_thompson5910):

you use the graph to find the left and right hand limits

jimthompson5910 (jim_thompson5910):

you basically start at x = 60, then you go to the left a bit as described above and you approach closer and closer to 60. You'll end up at y = 56

jimthompson5910 (jim_thompson5910):

to find the right hand limit, you start at x = 60, go to the right a bit, then approach it closer and closer to get y = 68

jimthompson5910 (jim_thompson5910):

does that make sense?

OpenStudy (anonymous):

yes i understand (i) and (ii) perfectly but i ned help with (iii) and (iv)

jimthompson5910 (jim_thompson5910):

it's shown by the graph because you use the graph to find these limits

jimthompson5910 (jim_thompson5910):

as for part iv, it looks like they increase the price every 20 miles

OpenStudy (anonymous):

increase the price by 12 dollars every 20 miles?

jimthompson5910 (jim_thompson5910):

yes, and this increase isn't continuous since it only happens at the beginning of each 20 mile interval

OpenStudy (anonymous):

ok thanks for ur help! 2 more please?

jimthompson5910 (jim_thompson5910):

sure

OpenStudy (anonymous):

The following piecewise function gives the tax owed, T(x), by a single taxpayer on a taxable income of x dollars. T(x) = I WILL POST TABLE (i) Determine whether T is continuous at 6061. (ii) Determine whether T is continuous at 32,473. (iii) If T had discontinuities, use one of these discontinuities to describe a situation where it might be advantageous to earn less money in taxable income.

jimthompson5910 (jim_thompson5910):

i) plug in x = 6061 into the first and second pieces (separately). If they produce the same T(x) value, then it's continuous at x = 6061

OpenStudy (anonymous):

they produce the same T(x) value

jimthompson5910 (jim_thompson5910):

so it's continuous at x = 6061

OpenStudy (anonymous):

ok so for (ii) you plug in 32473 into the second and third pieces?

jimthompson5910 (jim_thompson5910):

yes

jimthompson5910 (jim_thompson5910):

and see if they produce the same T(x) value

OpenStudy (anonymous):

and they are equal so continuous at 32473 too.

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

so (iii) is not applicable right?

jimthompson5910 (jim_thompson5910):

you are correct, it looks like T(x) has no discontinuities (but I would check all possible points of discontinuity)

OpenStudy (anonymous):

yes it doesnt i checked. thanks! 1 more?

jimthompson5910 (jim_thompson5910):

go for it

OpenStudy (anonymous):

and also for the limit question, for (i) and (ii) helder edwin gave me a different answer so im confused now..

jimthompson5910 (jim_thompson5910):

you should have the following \[ \large \lim_{x\to60^{-}}f(x) = 56 \] \[ \large \lim_{x\to60^{+}}f(x) = 68 \]

OpenStudy (anonymous):

ok. im just confused because there is a open dot at 68 and closed dot at 56 at x=60

OpenStudy (anonymous):

and the question is A statement Sn about the positive integers is given. Write statements Sk and Sk+1, simplifying Sk+1 completely. Sn: 1 + 4 + 7 + . . . + (3n - 2) = n(3n - 1)/2

jimthompson5910 (jim_thompson5910):

the open and closed dot are there to make sure that the function doesn't have multiple outputs for x = 60

jimthompson5910 (jim_thompson5910):

Sn: 1 + 4 + 7 + . . . + (3n - 2) = n(3n - 1)/2 Sk: 1 + 4 + 7 + . . . + (3k - 2) = k(3k - 1)/2

jimthompson5910 (jim_thompson5910):

Sk: 1 + 4 + 7 + . . . + (3k - 2) = k(3k - 1)/2 Sk+1: 1 + 4 + 7 + . . . + (3(k+1) - 2) = (k+1)(3(k+1) - 1)/2 Simplify the last line

OpenStudy (anonymous):

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