I will post a graph and using it you have to figure out 4 things. (i.) (lim x->60-) f(x) (ii.) (lim x->60+) f(x) (iii.) What can you conclude about (lim x->60) f(x)? How is this shown by the graph? (iv.) What aspect of costs of renting a car causes the graph to jump vertically by the same amount at its discontinuities?
do u know what \(x\to60-\) means??
as x approaches 60
from the left
@helder_edwin
yes. sorry, my laptop's battery went down.
now put yourself a little bit to the left of x=60 and then go up until u meet the function and then follow tha graph going leftwards with passing x=60
will the answer be the closed dot or the open dot at x=60?
if u go up a llitle bit to the left of x=60 u get to y=68 right?
yes
sorry gotta go!! remember \(x\to60-\) means x approaches 60 from the left but it never actually reaches x=60 so \[ \large \lim_{x\to60-}f(x)=68 \] in your graph.
ok so (i.) is 68 so (ii.) is 68 too?
recheck it (i.) is 56
but u r right (ii.) is 68
i think 1) (i) is 56 bcz it is to the left of 60 2) is 68 3) i think one sides limit exist at 60 not two sided
@mukushla yes ur right sorry
np sara :)
as u can see and aliza mentioned (lim x->60-) f(x) \(\neq\) (lim x->60+) f(x) so the limit (lim x->60) f(x) does not exist.
but the lim x->60- and lim x->60+ do exist right? and what would the answers be to these questions? (iii.) How is this shown by the graph? (iv.) What aspect of costs of renting a car causes the graph to jump vertically by the same amount at its discontinuities?
yes the left and right hand limits exist, just not the limit itself
left hand limit is shown and found by approaching x=60 from the left right hand limit is shown and found by approaching x=60 from the right
basically what the previous posters said
but (iii.) How is this shown by the graph? (iv.) What aspect of costs of renting a car causes the graph to jump vertically by the same amount at its discontinuities?
(iii) there is no limit but how is this shown by the graph?
you use the graph to find the left and right hand limits
you basically start at x = 60, then you go to the left a bit as described above and you approach closer and closer to 60. You'll end up at y = 56
to find the right hand limit, you start at x = 60, go to the right a bit, then approach it closer and closer to get y = 68
does that make sense?
yes i understand (i) and (ii) perfectly but i ned help with (iii) and (iv)
it's shown by the graph because you use the graph to find these limits
as for part iv, it looks like they increase the price every 20 miles
increase the price by 12 dollars every 20 miles?
yes, and this increase isn't continuous since it only happens at the beginning of each 20 mile interval
ok thanks for ur help! 2 more please?
sure
The following piecewise function gives the tax owed, T(x), by a single taxpayer on a taxable income of x dollars. T(x) = I WILL POST TABLE (i) Determine whether T is continuous at 6061. (ii) Determine whether T is continuous at 32,473. (iii) If T had discontinuities, use one of these discontinuities to describe a situation where it might be advantageous to earn less money in taxable income.
i) plug in x = 6061 into the first and second pieces (separately). If they produce the same T(x) value, then it's continuous at x = 6061
they produce the same T(x) value
so it's continuous at x = 6061
ok so for (ii) you plug in 32473 into the second and third pieces?
yes
and see if they produce the same T(x) value
and they are equal so continuous at 32473 too.
yes
so (iii) is not applicable right?
you are correct, it looks like T(x) has no discontinuities (but I would check all possible points of discontinuity)
yes it doesnt i checked. thanks! 1 more?
go for it
and also for the limit question, for (i) and (ii) helder edwin gave me a different answer so im confused now..
you should have the following \[ \large \lim_{x\to60^{-}}f(x) = 56 \] \[ \large \lim_{x\to60^{+}}f(x) = 68 \]
ok. im just confused because there is a open dot at 68 and closed dot at 56 at x=60
and the question is A statement Sn about the positive integers is given. Write statements Sk and Sk+1, simplifying Sk+1 completely. Sn: 1 + 4 + 7 + . . . + (3n - 2) = n(3n - 1)/2
the open and closed dot are there to make sure that the function doesn't have multiple outputs for x = 60
Sn: 1 + 4 + 7 + . . . + (3n - 2) = n(3n - 1)/2 Sk: 1 + 4 + 7 + . . . + (3k - 2) = k(3k - 1)/2
Sk: 1 + 4 + 7 + . . . + (3k - 2) = k(3k - 1)/2 Sk+1: 1 + 4 + 7 + . . . + (3(k+1) - 2) = (k+1)(3(k+1) - 1)/2 Simplify the last line
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