Mathematics
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OpenStudy (anonymous):
Which of the following is equivalent to: (4z+12)^4
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OpenStudy (anonymous):
256(z + 3)^4
4(z + 12)^4
4(z + 3)^4
256(z + 12)^4
OpenStudy (anonymous):
I need to know how to do this problem
mathslover (mathslover):
\[\large{(4z+12)^4 = [(4)(z+3)]^4}\]
mathslover (mathslover):
right?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
but thats not the right answer
OpenStudy (anonymous):
256(z + 3)^4 <==== is the answer
mathslover (mathslover):
wait :
\[\large{4^4 (z+3)^4 = 256 (z+3)^4}\]
mathslover (mathslover):
4^4 = 256
mathslover (mathslover):
hence the answer is :
\[\large{256(z+3)^4}\]
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mathslover (mathslover):
got it @Brent0423 ?
OpenStudy (anonymous):
could you further simplify it
mathslover (mathslover):
Yes but there is no need of it
mathslover (mathslover):
Since the options need no simplification further ..
r u getting my point @Brent0423 ?
OpenStudy (anonymous):
yes!
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OpenStudy (anonymous):
what about (x-5)^3
mathslover (mathslover):
\[\large{(x-5)^3=(x-5)(x-5)(x-5)}\]
mathslover (mathslover):
\[\large{(x-5)^2(x-5)=(x-5)^3}\]
right?
OpenStudy (anonymous):
ya
mathslover (mathslover):
what is (x-5)^2 ?
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OpenStudy (anonymous):
(x-5)(x-5) x^2-10x+25
mathslover (mathslover):
right good work , now we have:
\[\large{(x-5)^2(x-5)=(x^2-10x+25)(x-5)}\]
mathslover (mathslover):
\[\large{(x^2-10x+25)(x-5)}\]
\[\large{(x^2)(x)-5x^2-10x(x)-10x(-5)+25x-25(5)}\]
OpenStudy (anonymous):
okay i got it!
mathslover (mathslover):
good you can multiply them and solve..
also :
the formula for (a-b)^3 is:
\[\large{(a-b)^3=(a+b)(a^2-ab+b^2)}\]
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OpenStudy (anonymous):
X^3-15x^2+75x-125
mathslover (mathslover):
good gr8 work
OpenStudy (anonymous):
Which of the following is equivalent to
\[\frac{ \frac{ t+A }{ 5 } }{ t+A }, t \neq-A\]
OpenStudy (anonymous):
how do i figure this one out?
mathslover (mathslover):
ask this as a new question .. it will be answered there..