Question

how do you factor 6y+3xy−3x2y

Answer 1

each term has a common factor of \(3y\) so you can "factor it out" as the math teachers say, and write
\[3y(\text{something})\]
can you figure out the "something"?

Answer 2

yes it is 3y(2+y-^2) but somehow i have to factor it further and dont know how @satellite73

Answer 3

3y(2+y-x^2)

Answer 4

you are done

Answer 5

\[\large{6y+3xy-3x^2y}\]
\[\large{3y(2+x-x^2)}\]

Answer 6

anything left ? @michaelshaw

Answer 7

except the second term should be \(x\) and not \(y\)

Answer 8

no thats not the final answer when i put in online

Answer 9

hmn wait then I think there is further factorization also

Answer 10

oh maybe you can factor
\[2+x-x^2\]

Answer 11

\[\large{2+x-x^2}\]
\[\large{2+2x-x-x^2}\]
\[\large{-x^2+2x-x+2}\]
\[\large{-x(x-2)-1(x-2)}\]

Answer 12

not too many choices for this one
\[(2+x)(1-x)\] or
\[(1+x)(2-x)\] i think it is the second one

Answer 13

\[\large{2+x-x^2}\]
\[\large{-x^2+x+2}\]
\[\large{-x^2+2x-x+2}\]
\[\large{x(-x+2)+1(-x+2)}\]
\[\large{(x+1)(2-x)}\]

Answer 14

hence we can the answer as:
\[\large{3y(x+1)(2-x)}\]

Answer 15

got it @michaelshaw ?

Answer 16

thats still not the answer. when i put it in on xyz.com it says its wrong
@mathslover

Answer 17

did u type :

3y ( x+1 )( 2-x ) ?

Answer 18

oh i got it, thank you @mathslover im going to post another one i dont understant right now!