Question

my turn .. please answer this ..
differentiate: y= the square root of 2ax-x squared ..

Answer 1

@UnkleRhaukus

Answer 2

\[y=\sqrt{2ax}-x^2\]?
or\[y=\sqrt{2ax-x^2}\]?

Answer 3

the second one ..

Answer 4

\[y=\sqrt{2ax-x^2}=(2ax-x^2)^{1/2}\]

Answer 5

\[\frac{ a-x }{ \sqrt{2ax-x^{2}} }\]

Answer 6

y=√(2ax-x^2 )
y' = 1/(2√(2ax-x^2 )).d/dx(2ax-x^2)
y' = 1/(2√(2ax-x^2 )) (2a -2x)
y' = (a -x)/√(2ax-x^2 )

Answer 7

the chain rule
\[(f\circ g)'(x)=(f' \circ g)g'(x)\]