Question

Help help help!!! Can someone help me and explain step by step how to multiply this:

Answer 1

\[\frac{ x ^{3}+1 }{ x ^{3}-x ^{2}+x }\times \frac{ 6x }{ -54x-54 }\]

Answer 2

Do you agree that:?\[\frac{AB}{CD}*\frac{EF}{GH}=\frac{ABEF}{CDGH}\]

Answer 3

And do you agree that:?\[x^3+1=(x+1)(x^2-x+1)\]\[x^3−x^2+x=x(x^2-x+1)\]\[-54x-54=-54(x+1)\]\[6x=6*x\]

Answer 4

Yes, I do. Sorry, I was away. @Valpey

Answer 5

@Hero I only have 3 more questions. ): Please help?

Answer 6

Did you get that previous question correct?

Answer 7

No, because I didn't know how to figure out what it equaling with the square root.

Answer 8

Let's go back to it shall we?

Answer 9

Alright, well, I mean, we left off at \[\sqrt{0}=\sqrt{(x-5)^{2}}\]

Answer 10

Yes, and what is the square root of zero?

Answer 11

It's okay to say you don't know

Answer 12

Okay, how about this:

\(0^2 = 0\) right?

Answer 13

Yes.

Answer 14

Okay, so we can rewrite the equation like this:

\[\sqrt{0^2}=\sqrt{(x-5)^{2}}\]

And guess what? The square root and the square are inverses of each other, so they cancel. So what are you left with?

Answer 15

0=x-5

Answer 16

Precisely. So continue solving for x.

Answer 17

Thank you!! Okay, so another question is the one al the way at the top, want me to retype the equation?

Answer 18

I could have sworn I've seen that equation before.

Answer 19

You have but we never worked it out. Oh! And what exactly is a domain?

Answer 20

The domain of a function is the set of all x values that are valid for the function.

Answer 21

We should probably go back to that question. I could have sworn I posted something to help you.

Answer 22

I suppose you don't know how to get back to your own question.

Answer 23

I factored everything, but from there, I have no clue.

Answer 24

I'm going back to the other question. Are you coming with me?

Answer 25

The one at the top?

Answer 26

I'll just post a link to it.

Answer 27

Okay