Question

find all real solutions to 8x^3 + 27 = 0

Answer 1

try first to factorize your LHS

Answer 2

(2x-3) (4x-6x+9) I know that part. The thing is seeing if -3/2 is a solution or 3+ or - 3 square root of 8/ 4 is not or a possible solution also

Answer 3

the factorization is (2x+3)(4x^2-6x+9)=0
which gives 2x+3=0=>x=-3/2
and when you check the discriminant of the second factor you'll find out its negative=>
the only solution is x=-3/2

Answer 4

why does the the other factor (with the quadratic formula) is not a solution?