Question

can someone tell me how to do this?
Find all solutions in the interval [0, 2π).
2 sin2x = sin x

Answer 1

\[
4 \sin(x) \cos(x)=\sin(x) \\

4 \sin(x) \cos(x)-\sin(x)=0 \\
\sin(x) (4 \cos(x) -1)=0\\
\sin(x) =0 \\
4 \cos(x) -1 =0\\
\cos(x) =\frac 1 4
\]
Can you finish it now?

Answer 2

still confused >.<

Answer 3

When is sin(x) =0 for x between 0 and 2 Pi?