Question

Find equations of the lines through the given point parallel to the given line and perpendicular to the given line.
Point (7/8, 3/4)


Line 5x + 3y = 0

Answer 1

This is just really confusing me right now :/

Answer 2

slope the line parallel to 5x+ 3y = 0 is given by m = -5/3
then using the formula y = mx + c find the eqn , use the above slope and substitute x,y = (7/8,3/4)

for perpendicular line slope = -1/slope = 3/5
use the eqn y = mx + c substitute the m value and x,y values

Answer 3

alrighty, let me try this

Answer 4

did u get the answer??

Answer 5

still working on it haha sorry im slow

Answer 6

ok

Answer 7

i think i may still be doing it wrong...

Answer 8

is it okay if i convert to decimals?

Answer 9

ok if your comfortable with using decimals you can use it...
did find the slope ??

Answer 10

is it y= -2.2083?

Answer 11

you shouldnt find y

first take the case of parallel line

tell me the slope ??

Answer 12

-5/3

Answer 13

ok substitute the slope and x,y values in the equation y = mx + c to find c

Answer 14

3/4=-5/3(7/8)+c

Answer 15

find c

Answer 16

c= 2.654761905

Answer 17

ok. substitute the slope and c value in the eqn y = mx + c
to get the eqn of line parallel to 5x + 3y = 0

Answer 18

y=-5/3x+2.65471905

Answer 19

2.654761905*

Answer 20

ok. your right
now solve for perpendicular line

Answer 21

m=3/5

Answer 22

ok go ahead . follow same procedure and find the solution.

Answer 23

y=3/5x+.225

Answer 24

i think its correct... you followed same procedure right.....

Answer 25

yes i did haha

Answer 26

:)