Question

How fast would a ball have to be thrown upward to reach a maximum height of 196 ft? [Hint: Use the discriminant of the equation
16t2 − v0t + h = 0.

Answer 1

hmm i think the formula is not right. it think it is
\[h(t)=-16t^2+v_0t+h_0\]

Answer 2

i am also going to assume that the ball is thrown upward from the ground, otherwise we cannot now the answer.

Answer 3

yes

Answer 4

sorry i am in a rush this is due in less than 20 minutes

Answer 5

ok well you need to know what value of \(-\frac{v_0}{32}\) will give you 196

Answer 6

still not finding it

Answer 7

give me a minute, we can get it

Answer 8

try 112

Answer 9

\[h(t)=-16t^2+112t\] vertex at \(\frac{-b}{2a}=\frac{112}{32}=\frac{7}{2}\) and \(h(\frac{7}{2})=196\)

Answer 10

thanks

Answer 11

yw