How fast would a ball have to be thrown upward to reach a maximum height of 196 ft? [Hint: Use the discriminant of the equation
16t2 − v0t + h = 0.

Question

How fast would a ball have to be thrown upward to reach a maximum height of 196 ft? [Hint: Use the discriminant of the equation 
16t2 − v0t + h = 0.

anonymous · Answer

hmm i think the formula is not right.  it think it is 
$$h(t)=-16t^2+v_0t+h_0$$

anonymous · Answer

i am also going to assume that the ball is thrown upward from the ground, otherwise we cannot now the answer.

anonymous · Answer

yes

anonymous · Answer

sorry i am in a rush this is due in less than 20 minutes

anonymous · Answer

ok well you need to know what value  of $-\frac{v_0}{32}$ will give you 196

anonymous · Answer

still not finding it

anonymous · Answer

give me a minute, we can get it

anonymous · Answer

try 112

anonymous · Answer

$$h(t)=-16t^2+112t$$ vertex at $\frac{-b}{2a}=\frac{112}{32}=\frac{7}{2}$ and $h(\frac{7}{2})=196$

anonymous · Answer

thanks

anonymous · Answer

yw