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OpenStudy (rainbow_dash):
What is the inverse of y=3x^3-3
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jimthompson5910 (jim_thompson5910):
Swap x and y to get x = 3y^3 - 3 Now solve for y
OpenStudy (rainbow_dash):
so y = \[\sqrt[3]{x-3}/3\]
jimthompson5910 (jim_thompson5910):
close, it should be \[\Large y = \frac{\sqrt[3]{x+3}}{3}\] Notice is +3 and NOT -3
OpenStudy (rainbow_dash):
oh my bad simple mistake. thanks!
jimthompson5910 (jim_thompson5910):
np
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