Question

What is the inverse of y=3x^3-3

Answer 1

Swap x and y to get

x = 3y^3 - 3

Now solve for y

Answer 2

so y = \[\sqrt[3]{x-3}/3\]

Answer 3

close, it should be

\[\Large y = \frac{\sqrt[3]{x+3}}{3}\]

Notice is +3 and NOT -3

Answer 4

oh my bad simple mistake. thanks!

Answer 5

np