Question

Solve for x: ax-e
---- = m
bx+f

Answer 1

\[{ax-e\over bx+f}=m\]right?

Answer 2

yes thank u

Answer 3

multiply both sides by \(bx+f\) to get rid of the fraction first
what do you get?

Answer 4

ax-e= mbx+mf

Answer 5

good
now get the terms that contain x on one side of the equals sign, and the terms that do not contain x on the other

Answer 6

ax-mbx= mf+e
x(a-mb)=mf+e
x=\[\frac{ mf+e }{ a-mb }\]
is that the correct answer?

Answer 7

looks good to me :)

Answer 8

thanks so much i understand now!!

Answer 9

Anytime :D