Question

Algebra 2 question!
Find 4 consecutive integers such that when twice the 2nd is added to 3 times the 4th, the result is 31.

Answer 1

let first integer = x
second integer = x + 1
third integer = x + 2
fourth integer = x + 3

you know why right?

when twice the 2nd means 2(x+1)

3 times the fourth is 3(x+3)

it says the sum is 31 so...

2(x+1) + 3(x+3) = 31

do you know how to solve for x now? or do you need more help?

Answer 2

yes i do! I actually had it just like you, the 1= x
2=x+1 3=x+3 4= x+4

Answer 3

I just wasnt sure how to put it into an equation, thanks!

Answer 4

welcome