Question

how do i simplify In2x+In3-Inx

Answer 1

use the laws of logarithms
ln x + ln y = ln xy
lnx - ln y = ln x/y

so ln2x + ln3 = ln (3*2x) = ln 6x
so now you need to simplify ln 6x - ln x

Answer 2

thank you very much

Answer 3

yw

Answer 4

the answer in the book is just given as 6 can you explain that

Answer 5

by the second of the laws in my first post:

ln 6x - ln x
- ln (6x /x) = ln 6

Answer 6

thanks again

Answer 7

* = ln (6x/x) = ln 6

Answer 8

what about the laws for say In(x^3)+In(x^2)-Inx

Answer 9

- use same method as before
apply the first law
then second

Answer 10

im working on it

Answer 11

is it right to say that Ina-Inb = Ina/b

Answer 12

can you confirm i have used the correct logic In(x^3)/In(x^2) =Inx so Inx/Inx = 0