Question

Find a cubic function with the given zeros.

-7, 5, -3

Answer 1

you know these are zeros

this means

(x-a)(x-b)(x-c)=0

x= -7,5,-3
solve for a,b,c

Answer 2

i did that but i wasnt getting the answers that were shown

Answer 3

can you show me what you got?

Answer 4

x^3 +2x^2-35x

Answer 5

35*3 is not 35 ...

Answer 6

you're missing a constant
can you write it in the form of
(x-a)(x-b)(x-c)=0?

Answer 7

yea

Answer 8

these are my choices
f(x) = x3 + 5x2 - 29x - 105

f(x) = x3 + 5x2 - 29x + 105

f(x) = x3 + 5x2 + 29x - 105

f(x) = x3 - 5x2 - 29x - 105

Answer 9

i would ignore those for now

(x+7)(x-5)(x+3)=0
lets do this step by step

(x+7)(x-5)=x(x-5)+7(x-5)=???

Answer 10

ok...?

Answer 11

solve this

(x+7)(x-5)=x(x-5)+7(x-5)=

Answer 12

x2 - 5x + 7x + 21
x2 + 2x +21

Answer 13

7(x-5)= 7x-35, not 7x+21

Answer 14

jk i was doing 7(x+3)

Answer 15

...
(x+7)(x-5)= x^2+2x-35

now we multiply x+3 to this

Answer 16

(x^2+2x-35)(x+3)=???

(x^2+2x-35)(x+3)=x(x^2+2x-35)+3(x^2+2x-35)=???

Answer 17

ah i got it!!

Answer 18

thank you!!!