Question

If\[ x + iy = (1 - i \sqrt{3})^{100}\]
then (x,y) is?

Answer 1

\[ x + iy = (1 - i \sqrt{3})^{100}\]

Answer 2

FInd X and Y

Answer 3

\[x + iy = \frac{2^{100}}{2^{100}}(1 - i \sqrt{3})^{100}=2^{100}(\frac{1}{2} - i \frac{\sqrt{3}}{2})^{100}\]

Answer 4

ok?

Answer 5

yes

Answer 6

\[\frac{1}{2} - i \frac{\sqrt{3}}{2}=e^{-i\frac{\pi}{3}}\]

Answer 7

yes..))

Answer 8

well u continue

Answer 9

Any Hint:

Answer 10

\[(e^{i\theta})^n=e^{in\theta}\]

Answer 11

lol.....that...doesnt help...

2^100 ( cos6000 - i sin6000)

Answer 12

lol....))

Answer 13

cos6000= -1/2

Answer 14

i got...it thxxx...)))

Answer 15

\[\boldsymbol{MUKHSALA THXXX} \]

Answer 16

\[(e^{-i\frac{\pi}{3}})^{100}=e^{-i\frac{100\pi}{3}}= \cos \frac{100 \pi}{3}+i \sin \frac{100 \pi}{3}\]

Answer 17

\[\huge \color\yellow{LoL}\]