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Will the function \[\frac{ (x+1)(x-2) }{ (x-3) }\], have the slant asymptote???
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Yeah, at \(y = x + 2\)
(x+1)(x-2)=x^2-x-2
thought so.
Now, divide x^2-x-2 by x-3
thanks for all responses
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Remember: the quotient is always our slant asymptote.
Sorry... it'd actually be at y = x + 6
the reason I asked is because my texts solution only shows an asymptote at x=3
Ok:)
so my text is wrong?
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