Question

Each letter represents a unique number from 0 to 9.
Find the numbers corresponding to letters W,R,O,N,G such that it satisfies the relation given below:
WRONG
+WRONG
--------
RIGHT

Answer 1

my mom always told me two wrongs don't make a right....

Answer 2

i guess i should go rob that thief who mugged me last night.

Answer 3

well, in mathematics , multiply two negatives, u will get positive.

Answer 4

LEFT
+ LEFT
====
RIGHT

Answer 5

that's simpler,i guess,we get T directly coz T+T=T implies T=0

Answer 6

WRONG+WRONG= RIGHT ....let's say W=2, R=5, O=0 N=0, G=0

Answer 7

2500+2500=5000

Answer 8

the letters are unique.

Answer 9

okay...wait

Answer 10

i suppose it's safe to assume 2(WRONG) = RIGHT

Answer 11

^^ will that make it simpler?

Answer 12

20000W + 2000R + 200O + 20N + 2G = RIGHT

Answer 13

haha!! @lgbasallote using sixth sense...

Answer 14

20000W + 2000R + 200O + 20N + 2G = 10000R + 1000I + 100G + 10H + T

Answer 15

@lgbasallote may not be the best way

Answer 16

i have 2G=T,so t is even

Answer 17

w=3, r = 7, O = 3, N = 4, G = 6

37346
37346
_______ +
74692

Answer 18

W<5

Answer 19

@chihiroasleaf nice try,but u getting I=N

Answer 20

then let N = 3 lol

Answer 21

ahhh..., yes..., I did a mistake...,
I just realize that I found I = N :(

Answer 22

and W=O

Answer 23

w=2 , R=4 , O=7 , N=6 , G=5
R=4, I=9, G=5 , H=3 AND T=0

Answer 24

where did u get the solution??

Answer 25

I just did it ....

Answer 26

trial and error?

Answer 27

show work?

Answer 28

Ya... its a trial and error and a bit of logic

Answer 29

what logic?

Answer 30

W <= 4

Answer 31

Ya w<=4

Answer 32

And R=2W

Answer 33

R can be 2W+1, carry over 1 can be there.

Answer 34

Nope, it cannot be

Answer 35

if R>4,then there will be carry

Answer 36

WRONG
WRONG
-------
R I G HT
--------
2G = T <-- T should be 0, 2, 4, 6, 8

Answer 37

thats what i already written,W<5 and T even

Answer 38

@sauravshakya why R can't be 2W+1 ??

Answer 39

Another possibility could be:
W = 4, R = 9, O = 1, N = 5, G = 3
R = 9, I = 8, G = 3, H = 0, T = 6.
Since carrying the added value is inevitable, there are probably more solutions also.

Answer 40

how did u get that? trial and error
or some specific way?

Answer 41

Trial and error, mostly. Along with the described method above, W = 1/2 R, etc.

Answer 42

so i will assume there is no other specific way to solve such thing, okkk
thanks for the reply though.