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Mathematics 30 Online
OpenStudy (anonymous):

2(x+4)^4/3 = 512

OpenStudy (lgbasallote):

first divide both sides by 2.

OpenStudy (anonymous):

i get (x+4)^4/3 = 256

OpenStudy (lgbasallote):

right. now..take the 4th root of both sides

OpenStudy (anonymous):

x^4 + 256 = 256 ?

OpenStudy (anonymous):

oh wait

OpenStudy (anonymous):

sorry, can you explain why you take the 4th root?

OpenStudy (lgbasallote):

because you have (x+4)^4/3 this can also be written as \[\Large \implies [(x+4)^{\frac 13} ]^4\] to get rid of that raised to 4, you have to take the 4th root does that make sense?

OpenStudy (anonymous):

yes so it would be \[\sqrt[4]{x} + \sqrt[4]{4} = 4\]

OpenStudy (lgbasallote):

no... \[\sqrt{(a+b)^2} \implies a+b\] \[\sqrt{(a+b)^2} \ne \sqrt a + \sqrt b\] do you get what im implying?

OpenStudy (anonymous):

so would the x and the 4 that are under the sqrt signs be to the 3rd power as well?

OpenStudy (lgbasallote):

no..

OpenStudy (lgbasallote):

let me make another metaphor... \[\huge \sqrt{(a+b)^{\frac 23}} \implies (a+b)^{\frac 13} \]

OpenStudy (lgbasallote):

now do you get it?

OpenStudy (anonymous):

i'm sorry, i still don't get it

OpenStudy (lgbasallote):

my point is...if you take the 4th root of (x+4)^4/3 only 4 gets canceled. everything else should look the same

OpenStudy (anonymous):

Since you get get (x+4)^4/3 = 256 We need to do the inverse of the powers on the left side. Exponents multiply and divide. Cube both sides of the equation to get rid of the 1/3 power: (x + 4)^4 = 256^3 Take the 4th root of both side to get rid of the ^4: x + 4 = 256^3/4 x+ 4 = 64 x = 60

OpenStudy (lgbasallote):

\[\huge \sqrt[4]{(x+4)^{\frac 43}} \implies \sqrt[\cancel 4]{(x+4)^{\frac {\cancel 4}3}} \implies (x+4)^{\frac 13}\] dow do you get what i mean?

OpenStudy (anonymous):

but how come it doesn't seem like the 4th root is taken for the 256 on the right side?

OpenStudy (lgbasallote):

oh it is... im just showing the left side because you were wrong there. your right side was right

OpenStudy (lgbasallote):

\[\huge (x+4)^{\frac 13} = 4\] still following?

OpenStudy (anonymous):

yes

OpenStudy (lgbasallote):

good. now cube both sides to get rid of that raised to 1/3

OpenStudy (anonymous):

so it would be x^3 + 64 = 64

OpenStudy (lgbasallote):

no. again...you don't touch the ones INSIDE the parenthesis

OpenStudy (lgbasallote):

you just cancel the exponents

OpenStudy (anonymous):

oh yes, so it would be x+4 = 64, then subtract 4 from both sides and get x = 60

OpenStudy (lgbasallote):

right

OpenStudy (anonymous):

got it, thank you very much! :)

OpenStudy (lgbasallote):

welcome

OpenStudy (anonymous):

Corollary: raise each side to the reciprocal of 4/3. This gets rid of the 4/3 power, skips unnecessary steps, and you arrive at x + 4 = 64... x = 60 quickly

OpenStudy (anonymous):

is this after you divide the 2 on both sideS?

OpenStudy (lgbasallote):

you can also do much more advanced steps to get the answer in a second...i wonder why we don't do that

OpenStudy (anonymous):

it is, got the same answer doing it your way. thank you very much :)

OpenStudy (anonymous):

Yes that is after you divide by 2.

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