2(x+4)^4/3 = 512
first divide both sides by 2.
i get (x+4)^4/3 = 256
right. now..take the 4th root of both sides
x^4 + 256 = 256 ?
oh wait
sorry, can you explain why you take the 4th root?
because you have (x+4)^4/3 this can also be written as \[\Large \implies [(x+4)^{\frac 13} ]^4\] to get rid of that raised to 4, you have to take the 4th root does that make sense?
yes so it would be \[\sqrt[4]{x} + \sqrt[4]{4} = 4\]
no... \[\sqrt{(a+b)^2} \implies a+b\] \[\sqrt{(a+b)^2} \ne \sqrt a + \sqrt b\] do you get what im implying?
so would the x and the 4 that are under the sqrt signs be to the 3rd power as well?
no..
let me make another metaphor... \[\huge \sqrt{(a+b)^{\frac 23}} \implies (a+b)^{\frac 13} \]
now do you get it?
i'm sorry, i still don't get it
my point is...if you take the 4th root of (x+4)^4/3 only 4 gets canceled. everything else should look the same
Since you get get (x+4)^4/3 = 256 We need to do the inverse of the powers on the left side. Exponents multiply and divide. Cube both sides of the equation to get rid of the 1/3 power: (x + 4)^4 = 256^3 Take the 4th root of both side to get rid of the ^4: x + 4 = 256^3/4 x+ 4 = 64 x = 60
\[\huge \sqrt[4]{(x+4)^{\frac 43}} \implies \sqrt[\cancel 4]{(x+4)^{\frac {\cancel 4}3}} \implies (x+4)^{\frac 13}\] dow do you get what i mean?
but how come it doesn't seem like the 4th root is taken for the 256 on the right side?
oh it is... im just showing the left side because you were wrong there. your right side was right
\[\huge (x+4)^{\frac 13} = 4\] still following?
yes
good. now cube both sides to get rid of that raised to 1/3
so it would be x^3 + 64 = 64
no. again...you don't touch the ones INSIDE the parenthesis
you just cancel the exponents
oh yes, so it would be x+4 = 64, then subtract 4 from both sides and get x = 60
right
got it, thank you very much! :)
welcome
Corollary: raise each side to the reciprocal of 4/3. This gets rid of the 4/3 power, skips unnecessary steps, and you arrive at x + 4 = 64... x = 60 quickly
is this after you divide the 2 on both sideS?
you can also do much more advanced steps to get the answer in a second...i wonder why we don't do that
it is, got the same answer doing it your way. thank you very much :)
Yes that is after you divide by 2.
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