If 125 cal of heat is applied to a 60.0 g piece of copper at 22.0 Celsius, what will the final temperature be? The specific heat of copper is 0.0920 cal/g

Question

If 125 cal of heat is applied to a 60.0 g piece of copper at 22.0 Celsius, what will the final temperature be?  The specific heat of copper is 0.0920 cal/g

anonymous · Answer

$$q=mc \Delta T$$

plug in numbers and solve for Delta T, then you want to add that to the temp of the copper

anonymous · Answer

HUH??  I have no idea what you are talking about.  Care to break it down for an old lady?? :)

anonymous · Answer

$$125Cal=(60.0g )(0.0920 \frac{Cal}{g}) \Delta T$$

Now you have to solve for delta T

$$\frac{125 Cal}{(60.0 g)(0.0920 \frac{Cal}{g}}= \Delta T$$
$$\Delta T= 22.64$$

Now that you know what delta t equals you must plug it into another equation

$$\Delta T=T_f-T_i$$

we plug in the rest of our known values 

$$22.64=T_f-22$$

solve for T_f

$$44.64 C =T_f$$

anonymous · Answer

Thank you. Thank you!

anonymous · Answer

No problem good luck to you!