Question

what's the domain and the range of f(x)= square root of 4-x^2

Answer 1

under radical must be non negative

Answer 2

\[f(x)=\sqrt{4-x^2}\]

Answer 3

4 - x^2 > = 0

Answer 4

Solve for x

Answer 5

so the answer would be x=2 or -2 ??????

Answer 6

So.... Domain = [ -2 ,2]

Answer 7

@mukushla am i correct..))

Answer 8

yes u are...
fatemah do u know why? D=[-2,2]

Answer 9

yes because less or more than these values will give us negative values which cant be put under an even root :) so whats the value of the range??

Answer 10

ok :) make 'x' ur subject..and of course we know domain of inverse function is range of function itself

Answer 11

\[y=\sqrt{4-x^2}\]there is a restriction here y>=0

solve for x\[y^2=4-x^2\]\[x^2=4-y^2\]\[x=\sqrt{4-y^2}\]

Answer 12

so the range is also = [-2,2] ???

Answer 13

we had a restriction before doing inverse stuff\[y=\sqrt{4-x^2}\]this implies that \[y \ge0\]

Answer 14

so whats the value of the range??

Answer 15

[0,2] why?

Answer 16

so the values of the domain will give us 0 , 1 or 2 ????

Answer 17

every number between 0 and 2 :)