Question

If 16a^2 x 64=(4 x b)^2 and a and b are positive integers , then b is how many times greater than a?

Answer 1

Is that "mulitplied by" 64?

Answer 2

Well, working it out, it must be. What is (4b)(4b) ?

Answer 3

yeah i think so

Answer 4

Okay, I'll just wait till she replies, I have an answer but I'm not sure if it's right.

Answer 5

yes its multiplied by 64

Answer 6

Would it be all right to work through the problem? :)

Answer 7

@leah123 or are you just looking for an answer?

Answer 8

if you can, can you work out the problem

Answer 9

Okay :)

I'm going to draw this out cuz its easier to understand

Answer 10

Well, first can you determine what (4b)(4b) is?

Answer 11

or actually nvm, yes, answer @qpHalcy0n

Answer 12

thats what the whole thing is equal to

Answer 13

Darling, you're going to multiply the two together, to get what?

Answer 14

4 times 4

b times b

Answer 15

What is 4^2?

Answer 16

16b^2

Answer 17

Right, so the 16's go away. The squares go away.

Answer 18

64a = b. b is how many larger?

Answer 19

you factor out 16 from everything, if you'd like.

Answer 20

isn't it 16(a^2 * 4) = 16( b^2)?

Answer 21

divide by 16 from both sides, and get (a^2 * 4) = (b^2)? and then sqrt both sides? Is that possible @qpHalcy0n